8
\$\begingroup\$

Update:

STL synonym created instead of burnination: See

It appears that is "selectively" used for questions that utilize the Standard Template Library. However, this only applies to C++, and such code should already make use of the STL. Even if a C++ question doesn't utilize the STL for whatever reason, omitting this tag doesn't send any kind of signal. With over 2000 and only 59 questions, it hardly adds anything to the question.

enter image description here

\$\endgroup\$
  • \$\begingroup\$ such code should already make use of the STL unless reinventing-the-wheel of-course, in which case it's acceptable to disregard most of the STL. \$\endgroup\$ – Mast Jul 6 '15 at 21:59
  • \$\begingroup\$ Not to mention that the STL is not a thing anymore \$\endgroup\$ – Barry Jul 16 '15 at 21:12
6
\$\begingroup\$

NO, Do not Burninate the tag.

Make it a synonym of instead. This is better than burnination because it makes it impossible to then re-create the tag, and it also guides people correctly when they try to use it.

Additionally, a mod can then "merge" the tag, which will essentially silently (without "bumping") edit the tag off all current questions (which is what a burnination does anyway).

\$\endgroup\$
5
\$\begingroup\$

You have my vote to remove it. Firstly, it's actually a bit of a misnomer - the standard template library is actually an older library (architected mainly by Stepanov) that influenced the C++ standard library, which seems to have taken over the name. Secondly, I doubt many other languages have "standard library" as a tag. Finally, it's not all that descriptive - while not as large as the Java or Python standard libraries, there is a lot of stuff in the C++ standard library.

\$\endgroup\$
  • \$\begingroup\$ and, I would add, that the stl should be the sl because it is a lot mroe than just the template part..... but that's a different issue ;-) \$\endgroup\$ – rolfl Jul 6 '15 at 19:19
3
\$\begingroup\$

As long as all the question marked STL are already marked as C++ I have no issue with that.

\$\endgroup\$
  • \$\begingroup\$ For the record, you can search: [stl] -[c++] \$\endgroup\$ – rolfl Jul 6 '15 at 22:22

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .